Practical science guide

Lab Report Calculations

Turn raw readings into a result that another person can reproduce. Follow a complete density experiment, keep units and significant figures visible, then distinguish a reference comparison from repeatability and measurement uncertainty.

One worked experiment · Three original illustrations · Prefilled calculator checks

Try the density example

Give every calculation a traceable structure

A useful calculation section connects a physical question to recorded observations. Start with what you measured, write the relationship before substituting numbers, and finish with a result whose units and reporting rule are clear. Keep the original readings in a data table; replacing them with rounded results makes later checks harder.

  1. Name the quantity and method. Identify the sample, instrument, conditions and what the result will describe.
  2. List readings with units. Preserve recorded trailing zeros and distinguish measured values from defined constants or adopted references.
  3. Write the equation and substitute. Show conversions and enough arithmetic for someone to reproduce the result.
  4. Report and interpret. State the reporting convention, compare with a suitable reference if requested, and explain the limits of the method.
Lab calculation workflow from raw readings through unit checks and a reported result, with reference error and uncertainty kept distinct.
A reproducible lab calculation connects recorded readings, an equation, compatible units and a justified reporting convention.

The reference table summarizes this guide's hypothetical experiment. Swipe it on mobile, or focus the table and use the arrow keys. Wide equations support keyboard scrolling too.

Match the result to its question and assumptions
Quantity and conditionRelationshipWorked result
Displacement volume

Use compatible volume units and identify the two readings.

V=Vf−ViV=V_f-V_i10.0 mL10.0\,\mathrm{mL}
Density

For this mass and volume model, V>0V>0.

ρ=mV\rho=\frac{m}{V}2.50 g/mL2.50\,\mathrm{g/mL}
Magnitude of percent error

The adopted reference must satisfy xref≠0x_{\mathrm{ref}}\ne0.

E=∣x−xref∣∣xref∣×100%E=\frac{|x-x_{\mathrm{ref}}|}{|x_{\mathrm{ref}}|}\times100\%E≈3.85%E\approx3.85\%
Sample standard deviation

At least two observations; here n=3n=3.

s=∑i=1n(xi−xˉ)2n−1s=\sqrt{\frac{\sum_{i=1}^{n}(x_i-\bar{x})^2}{n-1}}0.0200 g/mL0.0200\,\mathrm{g/mL}

Worked example: density by water displacement

All readings in this guide are hypothetical teaching data. Suppose a nonporous solid is completely immersed, without trapped air, in a compatible liquid. Assume it does not dissolve, react or absorb liquid during the measurement. Record the actual conditions in a real experiment; a displaced-volume model is unsuitable if those assumptions fail.

Subtract the two recorded volumesTwo zero-based bars show recorded readings of 30.0 and 40.0 milliliters. Their difference is 10.0 milliliters. The bars represent readings, not a drawing of the cylinder or meniscus.Recorded volume
mL\mathrm{mL}
00
1010
2020
3030
4040
5050
30.030.0
Initial
40.040.0
Final
10.010.0

Subtract the two recorded volumes

Both bars start at zero and record hypothetical cylinder readings. The bracket is their difference, 10.0 mL10.0\,\mathrm{mL}. This chart does not model the cylinder shape, meniscus or instrument uncertainty.

1. Preserve the original observations

Sample mass
m=25.0 gm=25.0\,\mathrm{g}
Initial liquid reading
Vi=30.0 mLV_i=30.0\,\mathrm{mL}
Final immersed reading
Vf=40.0 mLV_f=40.0\,\mathrm{mL}

These are reported readings, not exact physical quantities. Record instrument identification and the method used to read the liquid level. The chart compares the numerical readings; it does not draw a meniscus or imply a calibrated uncertainty from the bar lengths.

2. Find the displaced volume

V=Vf−Vi=40.0 mL−30.0 mL=10.0 mLV=V_f-V_i=40.0\,\mathrm{mL}-30.0\,\mathrm{mL}=10.0\,\mathrm{mL}

Under the usual classroom subtraction rule, both readings extend to the same decimal place, so the difference retains that place. Check the subtraction and trailing zero.

3. Divide mass by displaced volume

ρ=mV\rho=\frac{m}{V}ρ=25.0 g10.0 mL=2.50 g/mL\rho=\frac{25.0\,\mathrm{g}}{10.0\,\mathrm{mL}}=2.50\,\mathrm{g/mL}

The quotient has three significant figures under that classroom rule. The output unit is mass per volume. The relationship is defined for positive volume in this experiment; a zero displaced volume cannot produce a finite density estimate for a positive mass. A final reading below the initial reading is a reason to inspect the procedure and input, not to report a negative density. OpenStax defines this density relationship.

The density tool checks units and the displacement arithmetic, but its display precision is a formatting choice. It does not infer the instrument uncertainty or automatically apply a classroom significant-figure rule from the spelling of the inputs. Verify the reported quotient separately.

Convert units without changing the physical result

Write units at the substitution step so cancellations are visible. Converting the numerator but leaving the denominator in a different scale can introduce large errors. NIST's quantity and unit conventions help keep symbols and values consistent.

1 mL=1 cm3=10−6 m31\,\mathrm{mL}=1\,\mathrm{cm}^{3}=10^{-6}\,\mathrm{m}^{3}2.50 gmL×10−3 kg1 g×106 mL1 m3=2.50×103 kg/m32.50\,\frac{\mathrm{g}}{\mathrm{mL}}\times\frac{10^{-3}\,\mathrm{kg}}{1\,\mathrm{g}}\times\frac{10^{6}\,\mathrm{mL}}{1\,\mathrm{m}^{3}}=2.50\times10^{3}\,\mathrm{kg/m}^{3}

The defined conversion factors are exact, so they do not reduce the significant figures of the measured result. Scientific notation makes the retained three figures explicit. A bare 25002500 can leave the intended reporting precision ambiguous, while 2.50×1032.50\times10^3 does not. Check the exact multiplier and scientific notation.

Use the Density Converter for a unit cross-check. A conversion tool verifies numerical equivalence; it cannot decide whether your sample, temperature or measurement model matches a reference source.

Keep significant figures separate from uncertainty

The common classroom rules serve different operations: addition and subtraction use the least precise adopted decimal place, while multiplication and division use the fewest adopted significant figures. These rules assume the recorded digits are meaningful. Your lab manual may instead require an explicit uncertainty method and a corresponding final reporting place.

For another example, the unrounded sum 12.11+0.3=12.4112.11+0.3=12.41 is reported as 12.412.4 under the decimal-place rule. It is not rounded to a single significant figure just because 0.30.3 contains one significant digit. Similarly, 2.52.5 and 2.502.50 represent the same numerical value but communicate different intended reporting precision. Check the addition example.

Keep guard digits during a chain of operations and avoid repeatedly rounding intermediate calculations. If a course requires rounding at specified stages, document that convention and follow it consistently. At an exact midpoint, apply the stated tie rule; different conventions can give different last digits. OpenStax's measurement chapter explains the usual introductory rules.

Significant figures do not supply a complete uncertainty budget. A last reported digit alone does not tell you about calibration, repeatability or shared effects between readings. Do not assign a standard uncertainty solely from the number of decimal places shown by a calculator.

Compare with a reference using percent error

Adopt a hypothetical practice reference of ρref=2.60 g/mL\rho_{\mathrm{ref}}=2.60\,\mathrm{g/mL}. This value is not a certified density or a claim about a real material. In an actual report, cite the substance, conditions and reference uncertainty. Convert both values to the same units before comparing them.

1. Keep the direction of the difference

Δρ=ρ−ρref=(2.50−2.60) g/mL=−0.10 g/mL\begin{aligned}\Delta\rho&=\rho-\rho_{\mathrm{ref}}\\&=(2.50-2.60)\,\mathrm{g/mL}\\&=-0.10\,\mathrm{g/mL}\end{aligned}

The negative sign says the result is below the adopted reference. The magnitude of that difference is a different quantity, so label it explicitly rather than silently discarding the sign.

2. Form the relative magnitude

E=∣2.50−2.60∣∣2.60∣×100%=5013%≈3.85%E=\frac{|2.50-2.60|}{|2.60|}\times100\%=\frac{50}{13}\%\approx3.85\%

Here 3.85%3.85\% is the percentage rounded to two decimal places for illustration; apply your own reporting rule if it requires fewer digits. The exact fraction is retained for checking. This is a reference comparison, not the uncertainty of the density result. Check the percent error. The prefilled tool compares the numerical values without a unit label; both article inputs are already in the same density unit.

3. Handle limits honestly

When the reference is zero, the percentage is undefined, including the case where both values are zero. An absolute difference remains available. There is no universal rule that an error below 5%5\% is acceptable; acceptance limits depend on the experiment, purpose and stated protocol. Inspect the zero-reference case.

Use “difference from the adopted reference” where the reference itself is uncertain. NIST's terminology discussion distinguishes measurement error from uncertainty and emphasizes the role of the comparison value.

Repeated measurements: mean, spread and standard error

Suppose comparable repeated determinations give densities 2.482.48, 2.502.50 and 2.52 g/mL2.52\,\mathrm{g/mL}. These can be reproduced from hypothetical masses 24.824.8, 25.025.0 and 25.2 g25.2\,\mathrm{g} with displaced volumes 10.0 mL10.0\,\mathrm{mL} for each trial. Calculate a density for each paired mass and volume first; in general, a ratio of averages need not equal an average of ratios.

Repeatability and a reference comparisonA point plot on a disclosed zoomed axis from 2.40 to 2.65 grams per milliliter shows three trial densities: 2.48, 2.50 and 2.52. The solid mean line is 2.50; the dashed hypothetical reference is 2.60. The observations cluster below the reference.Density — zoomed vertical axis
g/mL\mathrm{g/mL}
2.402.40
2.452.45
2.502.50
2.552.55
2.602.60
2.652.65
2.482.48
Trial 1
2.502.50
Trial 2
2.522.52
Trial 3

Repeatability and a reference comparison

The vertical axis is zoomed to 2.402.40–2.65 g/mL2.65\,\mathrm{g/mL}. Solid line: mean 2.50 g/mL2.50\,\mathrm{g/mL}. Dashed line: hypothetical reference 2.60 g/mL2.60\,\mathrm{g/mL}. A tight cluster does not establish agreement with the reference or identify a cause.

1. Find the arithmetic mean

ρˉ=2.48+2.50+2.523=2.50 g/mL\bar{\rho}=\frac{2.48+2.50+2.52}{3}=2.50\,\mathrm{g/mL}

2. Quantify trial-to-trial spread

s=(−0.02)2+02+(0.02)23−1=0.0200 g/mLs=\sqrt{\frac{(-0.02)^2+0^2+(0.02)^2}{3-1}}=0.0200\,\mathrm{g/mL}

The sample denominator is n−1n-1 when using these observations to estimate a larger population variance. The calculation requires at least two observations. This spread statistic has the same unit as density; the variance has the squared unit.

Verify the mean, sample spread and standard error

3. Do not relabel spread as total uncertainty

SE^(ρˉ)=sn=0.02003≈0.0115 g/mL\widehat{\mathrm{SE}}(\bar{\rho})=\frac{s}{\sqrt{n}}=\frac{0.0200}{\sqrt{3}}\approx0.0115\,\mathrm{g/mL}

For independent, comparable observations, this estimates the statistical standard error of their mean. It does not include every source of measurement uncertainty. A shared calibration contribution does not disappear just because the procedure is repeated. With only three trials, be especially careful about strong claims. Neither this standard error nor one sample standard deviation automatically defines a confidence interval.

All three practice results fall below the hypothetical reference. That illustrates why repeatability does not establish reference agreement. It does not identify a particular cause or by itself prove systematic bias. NIST's Type A guidance covers statistical uncertainty evaluation; the Basic Statistics Guide develops the spread calculations.

Error of a mean and mean absolute error answer different questions

Comparing the mean with one reference is different from averaging each trial's absolute deviation. Signed differences can cancel when trials lie on opposite sides of the reference. In this particular example every trial is below the same reference, so the mean absolute percentage error equals the percentage error of the mean. That equality is a property of these data, not a general identity. Inspect both batch summaries.

Optional: propagate explicitly assigned standard uncertainties

Use this section when the experiment calls for an uncertainty budget. Consider the same nominal mass and volume, but separately assign illustrative standard uncertainties um=0.10 gu_m=0.10\,\mathrm{g} and uV=0.10 mLu_V=0.10\,\mathrm{mL}. They are assumptions for this worked model, not values inferred from the trailing zeros or from the repeat trials above. Treat these two input quantities as uncorrelated and use a first-order approximation.

uρ2≈(∂ρ∂m)2um2+(∂ρ∂V)2uV2u_\rho^2\approx\left(\frac{\partial\rho}{\partial m}\right)^2u_m^2+\left(\frac{\partial\rho}{\partial V}\right)^2u_V^2∂ρ∂m=1V,∂ρ∂V=−mV2\frac{\partial\rho}{\partial m}=\frac1V,\qquad\frac{\partial\rho}{\partial V}=-\frac{m}{V^2}
Combine contributions in quadratureZero-based bars compare standard uncertainty contributions from mass, 0.010 grams per milliliter, and volume, 0.025, with their root-sum-square combination, approximately 0.0269. Input standard uncertainties are assigned separately and assumed uncorrelated.Standard uncertainty contribution
g/mL\mathrm{g/mL}
00
0.010.01
0.020.02
0.030.03
0.040.04
0.0100.010
Mass
0.0250.025
Volume
≈ ⁣0.0269\approx\!0.0269
Combined

Combine contributions in quadrature

The bars share a zero baseline. They show magnitudes after sensitivity scaling, all in g/mL\mathrm{g/mL}. For the assigned uncorrelated inputs, the combined standard uncertainty is the root sum of squares, not the sum of the first two bars.

1. Express both contributions in the output unit

∣1V∣um=0.010 g/mL\left|\frac1V\right|u_m=0.010\,\mathrm{g/mL}∣−mV2∣uV=0.025 g/mL\left|-\frac{m}{V^2}\right|u_V=0.025\,\mathrm{g/mL}

These are sensitivity-scaled standard uncertainty contributions, not the original mass and volume uncertainties placed on the same axis.

2. Combine the squared contributions

uρ≈0.0102+0.0252=29200 g/mLu_\rho\approx\sqrt{0.010^2+0.025^2}=\frac{\sqrt{29}}{200}\,\mathrm{g/mL}uρ≈0.0269 g/mLu_\rho\approx0.0269\,\mathrm{g/mL}

Within the stated linearized model, the radical is the exact arithmetic result; the propagation itself is an approximation. Choosing one significant digit for the reported uncertainty gives a result written as ρ=(2.50±0.03) g/mL\rho=(2.50\pm0.03)\,\mathrm{g/mL}, where the accompanying uncertainty is a standard uncertainty. A protocol may ask for two significant digits instead. State the convention and do not label this a 95%95\% interval. See NIST's propagation model and combined standard uncertainty guidance.

Displacement readings can share an uncertainty component

u2(Vf−Vi)=u2(Vf)+u2(Vi)−2 cov⁡(Vf,Vi)u^2(V_f-V_i)=u^2(V_f)+u^2(V_i)-2\,\operatorname{cov}(V_f,V_i)

This variance relationship includes covariance. Two readings from the same cylinder may share scale or calibration effects; assuming independence requires justification. The assigned volume uncertainty in the preceding example is already an input to that model. Do not add it again to two reading uncertainties or combine the repeated-trial standard error without considering what each component represents. Describe the actual method before choosing an uncertainty equation.

Turn the calculation into report wording

Use a short paragraph that connects the measured quantity, method, result and comparison. The following is an example of a classroom calculation statement; it does not claim a complete experimental uncertainty evaluation.

The hypothetical sample mass was 25.0 g25.0\,\mathrm{g}. The liquid reading changed from 30.030.0 to 40.0 mL40.0\,\mathrm{mL}, giving a displaced volume of 10.0 mL10.0\,\mathrm{mL}. Dividing mass by volume gave 2.50 g/mL2.50\,\mathrm{g/mL} under the classroom significant-figure rule. This was 0.10 g/mL0.10\,\mathrm{g/mL} below the adopted hypothetical reference of 2.60 g/mL2.60\,\mathrm{g/mL}, a percent error of approximately 3.85%3.85\% using the reference magnitude as the denominator.

For a real report, replace the practice data and reference with your own documented observations. Add the actual uncertainty evaluation if one is required. Discuss observed issues such as incomplete immersion or trapped air only when supported by your procedure or notes. Explain how a suspected issue could affect the model, and propose a check that would distinguish it from other causes.

Before submitting

  • Can someone recover each final result from the raw data and formula?
  • Do units cancel correctly, with defined conversions identified as exact?
  • Have you kept unrounded intermediate values and stated the final reporting rule?
  • Does the reference match the material and conditions, with a usable source?
  • Are trial spread, standard error, reference error and combined uncertainty labeled separately?
  • Have you reported missing information honestly instead of assigning an unsupported precision or acceptance threshold?

The Lab Calculators hub keeps the density, percent error and significant-figure tools together. Use the Mean, Median & Mode Calculator for a separate center check, and the Chemistry Concentration Basics guide when the report involves solutions rather than bulk density.

Practice before using your own data

Try each question first. The answers show the reporting assumption as well as the arithmetic.

Practice: a new mass and displaced volume

A sample has mass 18.6 g18.6\,\mathrm{g} and displaces 6.00 mL6.00\,\mathrm{mL}. What is its density under the classroom division rule?

ρ=18.66.00=3.10 g/mL\rho=\frac{18.6}{6.00}=3.10\,\mathrm{g/mL}

Both measured inputs have three significant figures, so the final zero is retained. This rule does not itself give a standard uncertainty.

Practice: a negative reference difference

A measured mass is 9.50 g9.50\,\mathrm{g} and the adopted reference is 10.00 g10.00\,\mathrm{g}. Find the signed difference and magnitude of percent error.

Δm=9.50−10.00=−0.50 g\Delta m=9.50-10.00=-0.50\,\mathrm{g}E=∣9.50−10.00∣10.00×100%=5.0%E=\frac{|9.50-10.00|}{10.00}\times100\%=5.0\%

The signed difference retains two decimal places here. Use the unrounded difference to calculate the percentage, rather than feeding a rounded intermediate back into the calculation.

Practice: what does a standard error describe?

Four independent, comparable trials have sample standard deviation 0.20 g/mL0.20\,\mathrm{g/mL}. Estimate the standard error of the mean.

SE^=0.204=0.10 g/mL\widehat{\mathrm{SE}}=\frac{0.20}{\sqrt4}=0.10\,\mathrm{g/mL}

This is the statistical standard error under those assumptions. It does not include a shared calibration component and does not establish a confidence interval without further conditions.

FAQ

Frequently Asked Questions

What belongs in a lab report calculation section?
Include the original readings with units, the quantity being found, the governing equation, a substitution line and a final result under a stated reporting rule. Explain conversions and identify any adopted reference. For repeated measurements, show enough trial data to reproduce the summary. Keep the instrument, conditions and uncertainty method identifiable elsewhere in the report rather than presenting an unexplained calculator screenshot.
When should I round laboratory calculations?
Keep guard digits while calculating and round the reported answer under your lab manual's rule. For a classroom sum or difference, the least precise adopted decimal place usually limits the result; for a product or quotient, use the fewest adopted significant figures. Thus 40.0−30.0=10.040.0-30.0=10.0 retains one decimal place, and 25.0/10.0=2.5025.0/10.0=2.50 retains three significant figures. A formal uncertainty budget may set the reporting place differently.
Are significant figures the same as measurement uncertainty?
No. Trailing zeros and the last reported digit communicate a reporting convention, but they do not specify every source of uncertainty. Calibration, resolution, repeatability and the measurement method can all matter. Do not turn the spelling 25.0 g25.0\,\mathrm{g} into an assumed standard uncertainty automatically. State a justified uncertainty separately, including whether it is a standard or expanded uncertainty and how it was evaluated.
How do I calculate percent error, and what if the reference is zero?
For a nonzero adopted reference, divide the absolute difference by the magnitude of that reference and express the ratio as a percentage: E=∣x−xref∣∣xref∣×100%E=\frac{|x-x_{\mathrm{ref}}|}{|x_{\mathrm{ref}}|}\times100\%. The signed difference separately shows direction. With a zero reference the percentage is undefined, even if the measured value is also zero; report an absolute difference or a justified alternative measure. A universal acceptable percentage does not exist.
Should I average the measurements or their percentage errors?
State which question you are answering. Error of the mean compares the arithmetic mean with one adopted reference. Mean absolute percentage error first takes each trial's absolute percentage error and then averages those percentages. They can differ because positive and negative deviations can cancel in a mean. Neither calculation replaces the sample standard deviation, which describes the spread of the trial results.
Can I use standard deviation as the uncertainty of the mean?
Sample standard deviation describes trial-to-trial spread. For independent, comparable observations, the estimated standard error of their mean is s/ns/\sqrt{n}. That is a statistical component, not automatically the complete measurement uncertainty. Shared calibration effects need separate treatment and are not removed by repeating the same procedure. Neither one standard deviation nor one standard error is automatically a 95%95\% confidence interval.
Why can two volume readings have correlated uncertainties?
Initial and final readings made with the same cylinder can share calibration or scale effects. An uncertainty in their difference therefore depends on the covariance as well as the two individual variances. Assuming independent readings without justification can misstate the result. Record the instrument and method, use the uncertainty model required by the experiment, and keep the classroom decimal-place rule distinct from an uncertainty propagation calculation.
What should I cite for a reference density or an unusual result?
Cite the actual source of the adopted value, including the substance, composition, temperature and other relevant conditions. Record any stated reference uncertainty and make units compatible before comparing. Our practice reference is deliberately hypothetical and must not be cited as a material property. For an unusual result, explain observed limitations and testable causes; do not invent a specific systematic error merely because three trials differ from the reference.

Sources and verification method

Primary references support the measurement principles below. The numerical experiment, assigned uncertainties and practice reference are original hypothetical examples. Exact rational arithmetic and symbolic derivatives independently check the examples and figure geometry; the linked calculators provide a separate implementation check. No real experiment or certified material measurement is claimed.

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Written and maintained by the Toolarithm editorial team. The method was last reviewed on . No independent professional review is claimed.

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