Measurement guide

Common Unit Conversions

Check factors, offsets and references.

Common unit conversion chart

Convert mass, temperature, speed and pressure by choosing the right relationship first. Most unit changes use a factor. Temperature readings need an offset, and pressure readings need a clearly stated reference.

Use the chart for quick lookups, then follow the worked examples to see unit cancellation, reverse checks and sensible rounding. Each example link opens a free converter with the inputs already selected. Examples use nominal values to make the arithmetic reproducible; real measurements retain their original precision.

Keep the full source unit name with the value. This chart uses international length definitions and avoirdupois mass unless stated otherwise. The pressure factors change units only; gauge and absolute reference choices are handled separately below.

Exact relationships and explicitly rounded approximations
Quantity or unitRelationshipConvention
Avoirdupois pound1 lb=0.45359237 kg1\,\mathrm{lb}=0.45359237\,\mathrm{kg}Exact; ordinary mass, not pound-force.
Avoirdupois ounce1 oz=28.349523125 g1\,\mathrm{oz}=28.349523125\,\mathrm gExact; not a troy ounce or a fluid ounce.
Metric tonne1 t=1000 kg1\,\mathrm t=1000\,\mathrm{kg}Exact; label tonne explicitly.
US short ton1 tonUS=907.18474 kg1\,\mathrm{ton}_{\mathrm{US}}=907.18474\,\mathrm{kg}Exact; two thousand avoirdupois pounds.
Imperial long ton1 tonImp=1016.0469088 kg1\,\mathrm{ton}_{\mathrm{Imp}}=1016.0469088\,\mathrm{kg}Exact; two thousand two hundred forty pounds.
Statute mile per hour1 mph=1.609344 km/h1\,\mathrm{mph}=1.609344\,\mathrm{km/h}Exact; international mile.
Road speed to SI1 km/h=518 m/s1\,\mathrm{km/h}=\frac{5}{18}\,\mathrm{m/s}Exact; divide the numerical value by 3.6.
Nautical knot1 kn=1.852 km/h1\,\mathrm{kn}=1.852\,\mathrm{km/h}Exact; one international nautical mile per hour.
Standard atmosphere1 atm=101.325 kPa1\,\mathrm{atm}=101.325\,\mathrm{kPa}Exact defined unit; not every local atmospheric pressure.
Bar1 bar=100 kPa1\,\mathrm{bar}=100\,\mathrm{kPa}Exact; bar and standard atmosphere differ.
Hectopascal and millibar1 hPa=1 mbar=100 Pa1\,\mathrm{hPa}=1\,\mathrm{mbar}=100\,\mathrm{Pa}Exact; commonly used for weather.
Pound-force per square inch1 psi≈6.894757293 kPa1\,\mathrm{psi}\approx6.894757293\,\mathrm{kPa}Rounded decimal; defined using standard gravity and the international inch.

Factor references: NIST conversion method and NIST quantity tables. Length, area and liquid-volume charts appear in our Metric vs Imperial guide.

Unit relationship diagram for pounds to kilograms, Celsius to Fahrenheit, miles per hour to kilometers per hour, and the difference between gauge and absolute pressure.
Representative exact factors and formulas from the mass, temperature, speed, and pressure guide.

Choose the conversion method before calculating

  1. Identify the quantity and convention. A pound of mass, a pound-force and a fluid ounce describe different quantities. Check whether a temperature is a reading or a change, and whether pressure is gauge, absolute or a difference.
  2. Arrange units to cancel. Put the unwanted unit in the denominator of a conversion factor. For speed, convert both distance and time. If the surviving unit is not the intended answer unit, fix the setup before multiplying.
  3. Apply offsets only when needed. Temperature readings use scale-specific zero points. A pressure-reference conversion uses the stated local atmosphere. These additions are not ordinary multiplicative unit changes.
  4. Check magnitude, reverse and round. Convert back with unrounded values and compare with the original input. Keep guard digits until the final step, then report units and measurement precision together.
150 lb×0.45359237 kg1 lb=68.0388555 kg150\,\cancel{\mathrm{lb}}\times\frac{0.45359237\,\mathrm{kg}}{1\,\cancel{\mathrm{lb}}}=68.0388555\,\mathrm{kg}

The cancellation marks show why this factor is multiplied. Flipping the factor would leave the wrong units. An exact definition supports an exact nominal calculation, but it does not imply a weighing instrument measured all the digits shown.

Example: pounds to kilograms

A shipping record lists a nominal mass of 150 lb150\,\mathrm{lb}. Find kilograms using the international avoirdupois pound, the convention used for ordinary shipping and body-mass labels.

  1. Select the exact definition: 1 lb=0.45359237 kg1\,\mathrm{lb}=0.45359237\,\mathrm{kg}.
  2. Multiply the numerical mass: 150×0.45359237=68.0388555150\times0.45359237=68.0388555. Attach kilograms to the result.
  3. For a display rounded to two decimal places, report 68.04 kg68.04\,\mathrm{kg}. Check the unrounded answer by dividing: 68.0388555/0.45359237=15068.0388555/0.45359237=150.

Do not use a rounded mental estimate as the stored conversion factor. For precious metals, choose troy units explicitly. For a label that just says “ton,” establish whether it means US short ton, Imperial long ton or metric tonne before converting.

Check this pounds-to-kilograms example

Example: a temperature reading versus a change

Let cc and ff be the numerical readings in degrees Celsius and Fahrenheit. The formulas apply to those scale readings; they are not dimensionless temperature quantities. Kelvin readings use TT in the final relationship below.

f=95c+32c=59(f−32)f=\frac95c+32\qquad c=\frac59(f-32)T=(c+273.15) KT=(c+273.15)\,\mathrm K
  1. Start with a reading of 77 ∘F77\,{}^\circ\mathrm F. Subtract the Fahrenheit offset: 77−32=4577-32=45.
  2. Apply the scale factor: 45×5/9=2545\times5/9=25. The equivalent reading is 25 ∘C25\,{}^\circ\mathrm C.
  3. Check the reverse: 25×9/5+32=7725\times9/5+32=77. The same temperature is 298.15 K298.15\,\mathrm K.

Now consider a rise from 20 ∘C20\,{}^\circ\mathrm C to 30 ∘C30\,{}^\circ\mathrm C. The change is 10 ∘C10\,{}^\circ\mathrm C, so the Fahrenheit change is 18 ∘F18\,{}^\circ\mathrm F. The readings are 68 ∘F68\,{}^\circ\mathrm F and 86 ∘F86\,{}^\circ\mathrm F; subtracting them cancels the offset.

Δf=95Δc=95(10)=18\Delta f=\frac95\Delta c=\frac95(10)=18

A negative temperature change is a fall and remains valid. A kelvin temperature reading below absolute zero is outside this ordinary conversion model. Kelvin uses no degree symbol. NIST explains the scale relationships.

Example: miles per hour to SI speed

Convert a nominal speed of 60 mph60\,\mathrm{mph} to both kilometers per hour and meters per second. Use the international statute mile, not the nautical mile. An hour contains exactly 36003600 seconds.

  1. For road-speed units, use 1 mi=1.609344 km1\,\mathrm{mi}=1.609344\,\mathrm{km}.60 mph×1.609344 km1 mi=96.56064 km/h60\,\mathrm{mph}\times\frac{1.609344\,\mathrm{km}}{1\,\mathrm{mi}}=96.56064\,\mathrm{km/h}
  2. For meters per second, convert the distance and the time denominator.60 mi1 h×1609.344 m1 mi×1 h3600 s=26.8224 m/s\frac{60\,\mathrm{mi}}{1\,\mathrm h}\times\frac{1609.344\,\mathrm m}{1\,\mathrm{mi}}\times\frac{1\,\mathrm h}{3600\,\mathrm s}=26.8224\,\mathrm{m/s}
  3. Check independently: 96.56064/3.6=26.822496.56064/3.6=26.8224. Rounded to two decimal places, the SI result is 26.82 m/s26.82\,\mathrm{m/s}.

For motion calculations, convert speed before using it with time in seconds or acceleration in SI units. A knot uses a nautical mile, and Mach needs the local speed of sound; neither can be substituted for statute miles per hour without changing the definition.

Example: psi to kPa, then gauge to absolute

Suppose a gauge reads 35 psi35\,\mathrm{psi}. First convert units without changing its reference. The exact psi factor follows from pound-force at standard gravity and the international inch; the decimal shown here is rounded.

pg=35 psi×6.894757293… kPa1 psi≈241.317 kPap_{\mathrm g}=35\,\mathrm{psi}\times\frac{6.894757293\ldots\,\mathrm{kPa}}{1\,\mathrm{psi}}\approx241.317\,\mathrm{kPa}

That answer is still gauge pressure. To obtain absolute pressure, assume a local atmospheric pressure of 100 kPa100\,\mathrm{kPa} for this example. Add it to the unrounded gauge result, not to the original value in psi.

pabs=pg+patmp_{\mathrm{abs}}=p_{\mathrm g}+p_{\mathrm{atm}}pabs≈241.317 kPa+100 kPa=341.317 kPap_{\mathrm{abs}}\approx241.317\,\mathrm{kPa}+100\,\mathrm{kPa}=341.317\,\mathrm{kPa}
One pressure, two reference pointsA gauge pressure of 35 psi is approximately 241.317 kilopascals. With an assumed local atmosphere of 100 kilopascals, absolute pressure is approximately 341.317 kilopascals. All bars use the same linear scale starting at vacuum.Local atmosphere
100 kPa100\,\mathrm{kPa}
Gauge pressure
≈241.317 kPa\approx241.317\,\mathrm{kPa}
Absolute pressure
00
100100
200200
300300
400400
≈341.317 kPa\approx341.317\,\mathrm{kPa}
kPa\mathrm{kPa}
The gold bar begins at the assumed local atmosphere; the black bar begins at vacuum. Adding the atmospheric part changes the reference. Changing units alone leaves that reference unchanged. This is a linear pressure comparison, not a diagram of a physical gauge.

The assumed local atmosphere is intentionally different from the defined standard atmosphere, 1 atm=101.325 kPa1\,\mathrm{atm}=101.325\,\mathrm{kPa}. Local atmospheric pressure changes with altitude and weather. Use the measured reference when a real calculation depends on it. Subtracting that same reference from the absolute result recovers the gauge pressure.

Negative gauge pressure can describe a partial vacuum; zero gauge pressure means equality with the local atmosphere, not zero absolute pressure. The atmospheric term is absent when merely converting a pressure difference. OpenStax explains the reference distinction.

Report precision and unit labels honestly

A calculator can show more digits than the original measurement justifies. Treat exact definitions differently from measured inputs: carry extra digits during arithmetic, then round the final value according to the measurement uncertainty or the reporting requirements. A short rounded display is useful, but do not feed it into a reverse calculation to judge the accuracy of the underlying factor.

Prefixes are case-sensitive. Milli and mega do not mean the same thing. Area and volume factors also need the corresponding power of the length factor; applying a length conversion once to a square or cubic measure gives the wrong dimensions. See the worked dimensional examples in Metric vs Imperial and the precision guidance in Lab Report Calculations.

For recipes, label US liquid or Imperial capacity and keep mass separate from volume. Ingredient density is needed to convert between grams and a volume measure. Our Kitchen Conversions guide explains that additional assumption. For measured results, use the Significant Figures Calculator to check presentation after completing the conversion.

Practice with worked answers

Try these nominal-value exercises before opening the answers. State the conversion direction and the pressure reference, then check the remaining units.

Convert two avoirdupois pounds to grams.
2 lb×0.45359237 kg1 lb×1000 g1 kg=907.18474 g2\,\mathrm{lb}\times\frac{0.45359237\,\mathrm{kg}}{1\,\mathrm{lb}}\times\frac{1000\,\mathrm g}{1\,\mathrm{kg}}=907.18474\,\mathrm g

Use the exact kilogram definition first, then the gram prefix. This is mass; no density assumption is needed.

Convert ninety kilometers per hour to meters per second.
90 km/h×1000 m1 km×1 h3600 s=25 m/s90\,\mathrm{km/h}\times\frac{1000\,\mathrm m}{1\,\mathrm{km}}\times\frac{1\,\mathrm h}{3600\,\mathrm s}=25\,\mathrm{m/s}

Hours cancel from the denominator. Multiplying by seconds per hour instead would produce the wrong dimensions.

Find gauge pressure from 250 kilopascals absolute with a local atmosphere of 100 kilopascals.
pg=250 kPa−100 kPa=150 kPap_{\mathrm g}=250\,\mathrm{kPa}-100\,\mathrm{kPa}=150\,\mathrm{kPa}

Subtract the local atmospheric reference because the input is absolute. Label the answer as gauge pressure; the unit alone does not carry that information.

Common conversion questions

Should I multiply or divide to convert units?

Write the conversion factor as a fraction with the original unit in its denominator and the desired unit in its numerator. The original units then cancel. For pounds to kilograms, multiply by the kilograms-per-pound factor. To reverse that conversion, divide by the same factor. Estimate the size first: the number of kilograms should be smaller than the number of pounds for the same positive mass.

Is a pound of mass the same as a pound-force?

No. An avoirdupois pound is a mass unit, with 1 lb=0.45359237 kg1\,\mathrm{lb}=0.45359237\,\mathrm{kg}. Pound-force is a force unit defined using standard gravity. A mass converter should not silently treat the two as interchangeable. Likewise, an ounce of mass cannot become a fluid ounce of volume without knowing the material density and the intended fluid-ounce convention.

Does a temperature change use the Fahrenheit offset?

No. The offset applies when converting a temperature reading between scales with different zero points. When you subtract two readings, that offset cancels. A rise of 10 ∘C10\,{}^\circ\mathrm C is a rise of 18 ∘F18\,{}^\circ\mathrm F. Use the difference mode in the temperature converter and retain the word rise, fall or change so the result cannot be mistaken for a final reading.

Does converting psi to kPa change gauge pressure into absolute pressure?

No. A unit change preserves the pressure reference. If the input is gauge pressure, its value in kilopascals remains gauge pressure. To calculate absolute pressure, also add the local atmospheric pressure expressed in matching units. State that reference explicitly; a standard atmosphere is a defined unit and does not automatically describe local weather or altitude.

Are all conversion factors exact?

Many unit relationships are defined exactly, such as the international pound, inch and mile. A displayed decimal may still be rounded, especially when the exact relationship is a repeating fraction. Other conventions, including some mercury-column factors, depend on an adopted definition or table. Exact factors never create extra measurement precision: keep guard digits during arithmetic and round the final measured result appropriately.

Can I use one fixed factor for Mach or for gallons?

Not without context. Mach is a ratio to the local speed of sound, which depends on the medium and conditions, so it needs an explicit sound-speed reference. Gallons must be labeled as US liquid, US dry or Imperial. These ambiguities concern the meaning of the source value; a calculator cannot recover a missing convention from the number alone.

Sources and calculation conventions

Reviewed against the references below. Worked examples are original nominal calculations, with exact factors retained internally. Temperature formulas refer to numerical scale readings. Pressure examples identify whether the operation changes units, reference, or both.

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